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what is the concentration of acetic acid if three 50ml samples of actic acid were neutralized...

what is the concentration of acetic acid if three 50ml samples of actic acid were neutralized with 19.96ml, and 19.97 ml of 0.121M NaOH

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Answer #1

Given volume of acetic acid=50 mL

Concentration of NaOH=0.1231 M and volume to nuetralize acetic acid=average of all volumes=(19.96+19.97)/2

=19.965 mL

The balanced equation between acetic acid and NaOH is

CH3COOH + NaOH = CH3COONa+ H2O

Now find the moles of NaOH=molarityx volume=(0.121 mol/L)x0.019965 L=2.415x10-3 mol.

From the equation moles of NaOH=moles of acetic acid=2.415x10-3 mol

The concentration of acetic acid=moles/volume=2.415x10-3 mol/0.050 L=0.0483 M

[CH3COOH]=0.0483 M.

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