Review Topics
References
Chapter 14: EOC
A 1.500 L vessel was filled with 0.1540 mol CO and 0.4260 mol H2 . When this mixture came to equilibrium at a certain temperature, the vessel contained 0.1160 mol CO . Obtain the value of Kc for the following reaction:
CO +2H2 is in equilibrium to yield CH3OH . All are in gas phase.
=
concentration of CO = 0.1540 /1.50 = 0.1027 M
concentration of H2 = 0.4260 / 1.500 = 0.284 M
CO + 2 H2 --------------> CH3OH
0.1027 0.284 0
0.1027-x 0.284 -2x x
at equilibrium
concentration of CO = 0.1160 / 1.5 = 0.0773 M
0.1027-x = 0.0773
x = 0.0254
[H2] = 0.284 - 2 x 0.0254 = 0.2332 M
Kc = [CH3OH] / [CO][H2]^2
= 0.0254 / (0.0773)(0.2332)^2
= 6.04
Kc = 6.042
Get Answers For Free
Most questions answered within 1 hours.