Question

Industrially, hydrogen gas can be prepared by combining propane gas (C₃H₈) with steam at about 400°C. The products are carbon monoxide gas (CO) and hydrogen gas (H₂).

(a) Write a balanced equation for the reaction.



(b) How many kilograms of H₂ can be obtained from 3.95 ×10³ kg of propane?
____×10____kg H₂ gas

Answer 1

1)

C3H8 + 3 H2O —> 3 CO + 7 H2

2)

Molar mass of C3H8,

MM = 3*MM(C) + 8*MM(H)

= 3*12.01 + 8*1.008

= 44.094 g/mol

mass of C3H8 = 3.95*10^3 Kg = 3.95*10^6 g

mol of C3H8 = (mass)/(molar mass)

= 3.95*10^6/44.09

= 8.958*10^4 mol

According to balanced equation

mol of H2 formed = (7/1)* moles of C3H8

= (7/1)*8.958*10^4

= 6.271*10^5 mol

Molar mass of H2 = 2.016 g/mol

mass of H2 = number of mol * molar mass

= 6.271*10^5*2.016

= 1.264*10^6 g

= 1.26*10^3 Kg

Answer: 1.26*10^3 Kg