Question

R1: 2CO(g) = C(s) + CO2(g), K = 7.7x10^-1

R2: COCl2(g) = CO(g) + Cl2(g), K = 1.7x10^2

R3: C(s) + CO2(g) + 2Cl2(g) = 2COCl2(g), Keqm =?

All reactions were performed at an identical temperature. Calculate Keqm for R3.

Answer 1

we need C(S) in the left, so invert R1

K converts to --> 1/K = 1/(7.7*10^-1) = 1.2987

now... we need COCl2 in the right, so invert R2:

K converts --> 1/K = 1/(1.7*10^2) = 0.00588

now, we need this with 2-COCl2 coefficient, so multiply by 2, the ffect in K is K^2

K --> 0.00588^2 = 0.0000345744

now...

Add reaction 1 and 2 (as modified)

this should give:

C(s) + CO2(g) + CO(g) + Cl2(g)= 2CO +COCl2(g)

cancelling common terms

C(s) + CO2(g) + Cl2(g)= COCl2(g)

K = K1*K2 = (1.2987)(0.0000345744) = 0.00004490177

then

Km = 0.00004490177