The following are the m/z values and attending peak intensities(in brackets) for the molecular ion and the M+1 peak of a compound. Propose a molecular formula.
M+. = 136 (61.7%)
M+1 =137 (6.6%)
Please explain step by step!
According to the given data:
The mass of molecular ion peak is an even number, i.e. there is no nitrogen in the molecular formula.
Rule of 13 (mass of one CH) gives 136/13 = 10 (with the remainder 6)
i.e. One of the possibilities is the molecular contains 10*CH and 6*H = C10H16
The second possibility is including one oxygen atom (mass = 16) instead of one CH4 unit (12 + 4), i.e. C9H12O
The third possibility is including two oxygen atoms (mass = 2*16) instead of two CH4 units (mass = 2*16), i.e. C8H8O2
Most probable structure is C9H12O
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