Question

Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. If 29.31 mL of a potassium hydroxide solution are needed to neutralize 1.800 grams of KHP, what is the concentration (mol/L) of the potassium hydroxide solution?

Answer 1

KHC8H4O4 + KOH -----> K2C8H4O4 + H2O

1 mole KHP = 1 mole KOH

no of mole of KHP reacted = w/mwt = 1.8/204.22 = 0.0088 mol

no of mole of KOH reacted = 0.0088 mol

concentration of KOH = n*(1000/v in ml)

                                   = 0.0088*(1000/29.31)

                                   = 0.3 mol/L