Question

Calculate the partial pressure of NH3 in a mixture of 25.0 g of NH3, 50.0 g of N2, and 25.0 g of H2 with 10.00 atm of total pressure. Calculate the partial pressure of NH3 in a mixture of 25.0 g of NH3, 50.0 g of N2, and 25.0 g of H2 with 10.00 atm of total pressure.

a) 2.50 atm

b)1.14 atm

c) 0.938 atm

d) 9.06 atm

Answer 1

no of moles of NH3   n_NH3     = W/G.M.Wt   = 25/17   = 1.47moles

no of moles of N2   n_N2            = W/G.M.Wt = 50/28   = 1.785 moles

no of moles of H2   n_H2         = W/G.M.Wt   = 25/2     = 12.5 moles

mole fraction of NH3 X_NH3    = n_NH3/n_NH3 + n_N2 + n_H2

                                               = 1.47/1.47+1.785+12.5     = 1.47/15.755 = 0.0938

partial pressure of NH3 P_NH3    = X_NH3 * P_T

                                                  = 0.0933*10 = 0.938atm

c) 0.938 atm