Calculate the value of
[H3O+] from the given [−OH] in each solution and label the solution as acidic or basic:
(a) [−OH] = 6.8 × 10−9M;
(b) [−OH] = 2.8 × 10−2M.
use the formula
ionic product of water
[H3O+][HO-] = 1.0 x 10^-14
and pH = -log[H3O+]
pOH = -log[HO-]
a.
given concentration is [HO-] = 1.0 x 10^-14
[H3O+] [ 6.8 × 10−9M] = 1.0 x 10^-14
[H3O+] = 1.0 x 10^-14 / 6.8 × 10−9M = 1.47 x 10^-6 M
pH = -log[H3O+] = -log[1.47 x 10^-6 M] = 5.83 M
pH is less than 7 so acidic
b.
given concentration is [HO-] =2.8 × 10−2M
[H3O+] [ 2.8 × 10−2M = 1.0 x 10^-14
[H3O+] = 1.0 x 10^-14 / 2.8 × 10−2M = 3.57 x 10^-13 M
pH = -log[H3O+] = -log[3.57 x 10^-13 M] = 12.44 M
pH is more than basic
Get Answers For Free
Most questions answered within 1 hours.