Question

The activation energy of a certain reaction is 35.1 kJ/mol . At 25 ∘C , the rate constant is 0.0160s−1. At what temperature in degrees Celsius would this reaction go twice as fast?

Given that the initial rate constant is 0.0160s−1 at an initial temperature of 25 ∘C , what would the rate constant be at a temperature of 200. ∘C for the same reaction described in Part A?

Answer #1

A)The activation energy of a certain reaction is 33.8 kJ/mol .
At 30 ∘C , the rate constant is 0.0170s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast?
B)Given that the initial rate constant is 0.0170s−1 at an
initial temperature of 30 ∘C , what would the rate constant be at a
temperature of 200. ∘C for the same reaction described in Part
A?

Part A:
The activation energy of a certain reaction is 50.0 kJ/mol . At
25 ∘C , the rate constant is 0.0110s−1. At
what temperature in degrees Celsius would this reaction go twice as
fast?
Express your answer with the appropriate units.
Part B:
Given that the initial rate constant is 0.0110s−1 at
an initial temperature of 25 ∘C , what would
the rate constant be at a temperature of
140. ∘C for the same reaction described in
Part A?
Express your...

Part A: The activation energy of a certain
reaction is 43.5 kJ/mol . At 23 ∘C , the rate constant is
0.0180s−1. At what temperature in degrees Celsius would this
reaction go twice as fast?
Part B: Given that the initial rate constant is
0.0180s−1 at an initial temperature of 23 ∘C , what would the rate
constant be at a temperature of 190. ∘C for the same reaction
described in Part A?

Part A: The activation energy of a certain reaction is 42.3
kJ/mol . At 29 ∘C , the rate constant is 0.0170s−1 . At what
temperature in degrees Celsius would this reaction go twice as
fast?
Part B: Given that the initial rate constant is 0.0170s−1 at an
initial temperature of 29 ∘C , what would the rate constant be at a
temperature of 120. ∘C for the same reaction described in Part
A?

Part A:
The activation energy of a certain reaction is 42.8 kJ/mol . At
28 ∘C , the rate constant is 0.0190s−1. At what temperature in
degrees Celsius would this reaction go twice as fast?
Part B:
Given that the initial rate constant is 0.0190s−1 at an initial
temperature of 28 ∘C , what would the rate constant be
at a temperature of 150 ∘C for the same reaction
described in Part A?

Part A
The activation energy of a certain reaction is 48.4 kJ/mol . At
24 ∘C , the rate constant is 0.0190s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast
T2 =
35 ∘C
Part B
Given that the initial rate constant is 0.0190s−1 at an initial
temperature of 24 ∘C , what would the rate constant be
at a temperature of 190. ∘C for the same reaction
described in Part A?
k2 =?

A. The activation energy of a certain reaction is 42.0 kJ/mol .
At 29 ∘C , the rate constant is 0.0190s-1. At what
temperature in degrees Celsius would this reaction go twice as
fast? Express your answer with the appropriate units.
B. Given that the initial rate
constant is 0.0190s-1 at an initial temperature of 29 C
, what would the rate constant be at a temperature of
120. ∘C for the same reaction described in Part
A?
Express your answer...

Part A
The activation energy of a certain reaction is 36.4 kJ/mol . At
21 ∘C , the rate constant is 0.0160s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast?
Express your answer with the appropriate units.
Hints
Part B
Given that the initial rate constant is 0.0160s−1 at an initial
temperature of 21 ∘C , what would the rate constant be
at a temperature of 130. ∘C for the same reaction
described in Part A?
Express your...

Part A
The activation energy of a certain reaction is 43.9 kJ/mol . At
28 ∘C , the rate constant is 0.0130s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast?
Express your answer with the appropriate units.
Part B
Given that the initial rate constant is 0.0130s−1 at an initial
temperature of 28 ∘C , what would the rate constant be
at a temperature of 100. ∘C for the same reaction
described in Part A?
Express your answer...

Part A: The activation energy of a certain reaction is 39.2
kJ/mol . At 24 ∘C , the rate constant is 0.0190s−1. At what
temperature in degrees Celsius would this reaction go twice as
fast? Express your answer with the appropriate units.
Part B: Given that the initial rate constant is 0.0190s−1 at an
initial temperature of 24 ∘C , what would the rate
constant be at a temperature of 150. ∘C for the same
reaction described in Part A?
Express your...

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