Question

Determine the heat of reaction for the process:

TiO2+ 4HCL---------> TiCl4+ 2H2 + O2

Using the information below

Ti + O2-------> TiO2 Delta H = -939.7 Kj

2 HCL-----------> H2 + Cl2 Delta H = -184.6

Ti + 2 Cl2-------------> TiCl4 Delta H= -804.2

Answer 1

Ti + O₂     TiO₂ H = -939.7 KJ

2 HCL       H₂ + Cl₂ H = -184.6 kJ

Ti + 2 Cl₂    TiCl₄ H= -804.2 kJ

The above equation can be rearranged as:

TiO₂    Ti + O₂     H = 939.7 KJ

4HCL    2H₂ + 2Cl₂    H = - 369.2 kJ

Ti + 2Cl₂       TiCl₄ H = - 804.2 kJ

Adding all above equations, we get:

TiO₂ + 4HCl TiCl₄ + 2H2 + O₂

H = 939.7 -369.2 - 804.2

= 237.7 kJ