A student needs to prepare a 0.1 mg total mixture with a mole fraction of urea (Xurea) = 0.4673. How much TCA and urea (in mg) is needed for this mixture?
Tatal mixture = 0.1 mg
Urea mole fraction = 0.4673
TCA mole fraction = 1 - 0.4673 = 0.5327
mole fraction of urea = mg of urea/(mg of urea +mg of TCA)
mg of urea = mole fraction of urea (mg of urea +mg of TCA)
= 0.4673 0.1 = 0.04673 mg
mg of urea = 0.04673 mg
mole fraction of TCA = mg of TCA/(mg of urea +mg of TCA)
mg of urea = mole fraction of TCA (mg of urea +mg of TCA)
= 0.5327 0.1 = 0.05327 mg
mg of TCA = 0.05327 mg
Get Answers For Free
Most questions answered within 1 hours.