1)Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.1000 M HNO3(aq) after 19.5 mL of the acid have been added. Kb of trimethylamine = 6.5 x 10-5.
2)Determine the volume in mL of 0.13 M KOH(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 42 mL of 0.23 M C6H5OH(aq). The Ka of phenol is 1.0 x 10-10.
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