Predict the ratios (%) in which these monochlorination products will be formed, remembering that a chlorine atom abstracts a secondary hydrogen about 4.5 times as fast as it abstracts a primary hydrogen.
In the chlorination of pentane gives a mixture of three monochlorinated products.
There are 6 primary hydrogens to get 1-chloropentane, 4 secondary hydrogens to get 2-chloropentane and
2 secondary hydrogens to get 3-chloropentane.
Therefore, Ratio of no. of hydrogens available to get 1-chloropentane vs 2-chloropentane vs 3-chloropentane
= 6 : 4 : 2
Given that a chlorine atom abstracts a secondary hydrogen about 4.5 times as fast as it abstracts a primary hydrogen.
Therefore, corresponding reactivity factor = 1 : 4.5 : 4.5
Final ratio = 1x 6 : 4.5x 4 : 4.5x 2
= 6:18:9
= 2:6:3
Therefore, Ratio three monochlorinated products = 1-chloropentane : 2-chloropentane : 3-chloropenatne = 2:6:3
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