Question

What is ΔGo (in kJ) at 464 K for the following reaction? PbO(g) + CO2(g) → PbCO3(s) PbO: ΔHfo = -219.0 kJ/mol and So = 66.5 J/K mol) PbCO3(s): ΔHfo = -699.1 kJ/mol and So = 131.0 J/K mol) CO2: ΔHfo = -393.5 kJ/mol and So = 213.6 J/K mol)

Answer 1

PbO(g) + CO2(g) → PbCO3(s)
PbO: ΔHfo = -219.0 kJ/mol and So = 66.5 J/K mol)
PbCO3(s): ΔHfo = -699.1 kJ/mol and So = 131.0 J/K mol)
CO2: ΔHfo = -393.5 kJ/mol and So = 213.6 J/K mol)

delta H = delta Hf(PbCO3) - delta Hf(PbO) - delta Hf(CO2)
               = (-699.1) - (-219) - (-393.5)
               = -86.6 KJ/mol
               = -86600 J/mol

delta S = delta Sf(PbCO3) - delta Sf(PbO) - delta Sf(CO2)
               = (131) - (66.5) - (213.6)
               = - 149.1 J/Kmol

Use:
delta G = delta H - T * delta S
                = -86600 - (464)*(-149.1)
                 = -17417.6 J/mol
                 = -17.42 KJ/mol
Answer: -17.42 KJ/mol