Calculate the standard potential and deltarGo for the reaction where NADH is oxidized to NAD+ if half-cell potentials are Eo (O2,H+ ,H2O)= 0.82V and Eo (NAD, H ,NADH+) = 0.32V .
2NADH --------> 2NAD+ + 2H + 2e- E0 = -0.32v
O2 + 2H+ +2e---------> H2O E0 = 0.82
E0 cell = E0red - E0oxd
= 0.82+0.32 = 1.14V
G0 = -nE0 cell* F
= -2*1.14*96500 = -220020J
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