Question

how many moles of CO2 are produced when 5.05 mol of ethane are burned in excess of oxygen

Answer 1

2 C2H6 (g ethane) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (l)

2 MOLE OF ETHANE YIELD   ------   4 MOLE OF CO2

5.05 MOLE OF ETHANE YIELDS ----- ?   

                   (SIMPLE CROSS MULTIPLICATION)

                                        ? = 5.O5 MOL X 4 MOL / 2 MOL = 10.1 MOL OF CO2 PRODUCED