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What volume of O2 at 912 mmHg and 35 ∘C is required to synthesize 23.5 mol...

What volume of O2 at 912 mmHg and 35 ∘C is required to synthesize 23.5 mol of NO?

Can someone please show me step by step.

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Answer #1

Answer -

This question includes mix concept of the mole concept and ideal gas law.

First, we write a balanced chemical reaction.


4 NH3 + 5 O2 ---------. 4 NO + 6 H2O ....[ Balanced Equation ]

moles of O2 required = ( 22.5 mol NO ) ( 5 mol O2 / 4 mol NO )

O2 required = 28.125 mole O2

or

Where,

n= number of moles, T =temperature , R = universal gas constant= 0.08205 atm - L per mol - K, V= volume and P=pressure

V = ( 28.125mole ) ( 0.08205 ) ( 35.0 + 273.15) / ( 916 / 760 ) (760mm Hg = 1atm)

V= 589.99 = 590 L

Hence,590L of O2 is required.

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