0.10 M NaOH
Is it molecular or Ionic?
Is it a strong, weak, or nonelectrolyte?
Is it acidic, Basic, or nuetral? (HBtB test)
A) ionic dissociation, molecular ionization, or molecular dissolution Equation:
B) additional hydrolysis equation (if needed to explain HBtB results)
a) NaOH is a Ionic compound. In consisting of Cation Na+ and an anion HO-.
b) NaOH is strong electrolyte. In aqueous medium NaOH readily ionizes as,
NaOH (aq) Na+ (aq) + HO- (aq)
c) Aqueous solution of NaOH is basic. The aqueous solution of NaOH due to complete ionization of naOH is reach in HO- concentration. Hence aq. NaOH is basic solution.
For 0.10 M NaOH
[HO-] = [NaOH] = 0.10 M
pOH = -log[HO-] = -log(0.10) = 1
pH = 14.0 - pOH = 14.0 - 1.0 = 13.0
d) No hydrolysis of ay species occurs in aq. NaOH solution.
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