Question

How many grams of BaSO4 are formed when a 250 mL of .800 M of sodium sulfate solution is added to 300.0 mL of aqueous 0.455 M BaCl2?(Hint: this is also a limiting reactant problem)

Answer #1

= 0.25 L

number of mol of Na2SO4,

n = Molarity * Volume

= 0.8*0.25

= 0.2 mol

volume OF BaCl2 , V = 300.0 mL

= 0.3 L

number of mol of BaCl2,

n = Molarity * Volume

= 0.455*0.3

= 0.1365 mol

Balanced chemical equation is:

Na2SO4 + BaCl2 ---> BaSO4 + 2 NaCl

1 mol of Na2SO4 reacts with 1 mol of BaCl2

for 0.2 mol of Na2SO4, 0.2 mol of BaCl2 is required

But we have 0.1365 mol of BaCl2

so, BaCl2 is limiting reagent

we will use BaCl2 in further calculation

Molar mass of BaSO4,

MM = 1*MM(Ba) + 1*MM(S) + 4*MM(O)

= 1*137.3 + 1*32.07 + 4*16.0

= 233.37 g/mol

According to balanced equation

mol of BaSO4 formed = (1/1)* moles of BaCl2

= (1/1)*0.1365

= 0.1365 mol

mass of BaSO4 = number of mol * molar mass

= 0.1365*2.334*10^2

= 31.9 g

Answer: 31.9 g

How many grams of precipitate formed when 4 mL of copper sulfate
were reacted with 2 mL of sodium sulfide?

How many grams of solid barium phosphate form when 48.3 mL of
0.087 M Barium Chloride reacts with 34.0 mL of 0.155 M Sodium
phosphate? What is the limiting reactant? if the percent yield is
76% how much barium phosphate is recovered?

(a) How many milliliters of 0.165 M HCl are needed to
neutralize completely 35.0 mL of 0.101 M
Ba(OH)2 solution?
________ ml
(b) How many milliliters of 2.50 M
H2SO4 are needed to neutralize 50.0 g of
NaOH?
_________ mL
(c) If 56.8 mL of BaCl2 solution is needed to
precipitate all the sulfate in a 544 mg sample of
Na2SO4 (forming BaSO4), what is
the molarity of the solution?
_________M
(d) If 47.5 mL of 0.250 M HCl solution...

(a) How many milliliters of 0.165 M HCl are needed to neutralize
completely 35.0 mL of 0.101 M Ba(OH)2 solution? ______ml
(b) How many milliliters of 3.50 M H2SO4 are needed to
neutralize 75.0 g of NaOH?
_______mL
(c) If 55.8 mL of BaCl2 solution is needed to precipitate all
the sulfate in a 544 mg sample of Na2SO4 (forming BaSO4), what is
the molarity of the solution?
________M
(d) If 47.5 mL of 0.375 M HCl solution is needed...

25.0 grams of sodium chloride are dissolved in 250 mL of
water:
A. What is the molarity of the sodium chloride solution?
B. If 50.0 mL of the solution is then added to an additional 250
ml of water, what is the new molarity?

A. You wish to prepare 198 grams of 10.3 %
Na3PO4. How many grams will need of sodium
phosphate and how many mL of water? Assume that the density of
water is 1.00 g / ml.
B. If 20.5 grams of an aqueous solution of cobalt(II) sulfate,
CoSO4, contains 2.84 grams of cobalt(II) sulfate, what
is the percentage by mass of cobalt(II) sulfate in the
solution?
C. An aqueous solution of lead nitrate,
Pb(NO3)2, contains 8.74 grams of lead nitrate...

How many grams of iron III sulfate form when 62.0 mL of 0.160 M
of Barium chloride reacts with 58.0 ml of 0.065 M os Sodium
Sulfate? Please show the steps necessary to reach the answer as
well.
This question is not in the textbook solutions section of
chegg.

How many grams of iron III sulfate form when 62.0 mL of 0.160 M
of Barium chloride reacts with 58.0 ml of 0.065 M os Sodium
Sulfate? Please show the steps necessary to reach the answer as
well. This question is not in the textbook solutions section of
chegg.

How many grams of sodium acetate must be added to a 150.0 mL
solution of 0.40 M acetic acid to prepare a buffer with a pH =
4.80?

When 5.00 grams of Al are added to 305 mL of a 0.69 M solution
of Hydrochloric acid, the products are a gas and an aqueous
solution of an ionic compound. How many grams of Al are left
unreacted?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 4 minutes ago

asked 17 minutes ago

asked 17 minutes ago

asked 18 minutes ago

asked 18 minutes ago

asked 30 minutes ago

asked 30 minutes ago

asked 36 minutes ago

asked 46 minutes ago

asked 49 minutes ago

asked 50 minutes ago

asked 53 minutes ago