Question

Calculate the hydronium ion, H3O , and hydroxide ion, OH–, concentrations for a 0.0360 M NaOH solution.

Answer 1

NaOH (aq.) ---------> Na⁺ (aq.) + OH^- (aq.)

0.0360 M                                     0.0360 M

Since NaOH is strong base it undergoes complete ionisation it form the respective ions.

Hence, [OH^-] = 0.0360 M

It is known that,

[H₃O⁺][OH^-] = 10^-14

[H₃O⁺] = 10^-14 / 0.0360

[H₃O⁺] = 2.78 * 10^-13 M