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Calculate the hydronium ion, H3O , and hydroxide ion, OH–, concentrations for a 0.0360 M NaOH...

Calculate the hydronium ion, H3O , and hydroxide ion, OH–, concentrations for a 0.0360 M NaOH solution.

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Answer #1

NaOH (aq.) ---------> Na+ (aq.) + OH- (aq.)

0.0360 M                                     0.0360 M

Since NaOH is strong base it undergoes complete ionisation it form the respective ions.

Hence, [OH-] = 0.0360 M

It is known that,

[H3O+][OH-] = 10-14

[H3O+] = 10-14 / 0.0360

[H3O+] = 2.78 * 10-13 M

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