Question

25.0 grams of sodium chloride are dissolved in 250 mL of water:

A. What is the molarity of the sodium chloride solution?

B. If 50.0 mL of the solution is then added to an additional 250 ml of water, what is the new molarity?

Answer #1

Calculated Molarity of following solutions
24.5g of sodium nitrate dissolved in a 275ml solution.
25.0 mL of a 0.125 M hyrochloric acid solution diluted with
water to 500.0 mL.
A solution of nitric acid with pH= 2.42

Suppose 1.35g of iron(II) chloride is dissolved in 250.mL of a
29.0mM aqueous solution of silver nitrate.Calculate the final
molarity of chloride anion in the solution. You can assume the
volume of the solution doesn't change when the iron(II) chloride is
dissolved in it.Round your answer to 3 significant
digits.

30.0 mL of 0.512 M sulfuric acid was added to 25.0 mL of 0.666 M
sodium
hydroxide.
a. Write the balanced chemical equation.
b. Determine the molarity of either
acid or base remaining after the
reaction.
c. Find the molarity if a 50.00 mL aliquot of
this solution is diluted to 250. mL.

In 250 mL of solution the following is dissolved:
40 mg calcium chloride
40 mg calcium citrate
800 mg sodium chloride
75 mg potassium chloride
20 mg sodium lactate
Find the osmolarity of the solution.

A student used 0.230g of oxalic acid dissolved in 50.0 mL of
water as a primary standard (MW 126.07 g/mol). 37.10 mL of sodium
hydroxide aqueous solution were required to titrate the sample.
What is the molarity of the sodium hydroxide solution? The
neutralization reactions is:

Suppose 3.10g of sodium iodide is dissolved in 250.mL of a
73.0mM aqueous solution of silver nitrate. Calculate the final
molarity of iodide anion in the solution. You can assume the volume
of the solution doesn't change when the sodium iodide is dissolved
in it. Round your answer to 2 significant digits.

measure 5 grams of sodium chloride (NaCl) and add to 50 ml of
distilled water in a graduated cylinder. stir the salt. this was a
failed attempt at making a 10% w/v solution. Determine the excess
volume by reading the volume of the graduated cylinder. the number
of ml in excess of 50 represents the volume displaced by the 5g of
dissolved NaCl.
The question for the above information is: What is the actual
percentage of NaCl (w/v)?
Please explain...

A 0.872 gram sample of an unknown monoprotic acid is dissolved
in 50.0 mL of water and titrated with a a 0.424 M aqueous sodium
hydroxide solution. It is observed that after 9.40 milliliters of
sodium hydroxide have been added, the pH is 3.350 and that an
additional 5.50 mL of the sodium hydroxide solution is required to
reach the equivalence point. (1) What is the molecular weight of
the acid? g/mol (2) What is the value of Ka for...

A 1.22 gram sample of an unknown monoprotic acid is dissolved in
25.0 mL of water and titrated with a a 0.299 M aqueous potassium
hydroxide solution. It is observed that after 10.4 milliliters of
potassium hydroxide have been added, the pH is 3.039 and that an
additional 19.4 mL of the potassium hydroxide solution is required
to reach the equivalence point. (1) What is the molecular weight of
the acid? g/mol (2) What is the value of Ka for...

What is the molality of a sodium chloride solution if 3.5 grams
of the salt is added to 998 g of water?
*Use 58.44 g/mol as the molecular mass of NaCl

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