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c. For the reaction SO2(g) + NO2(g) NO(g) + SO3(g), Keq = 10.8. A sample of...

c. For the reaction SO2(g) + NO2(g) NO(g) + SO3(g), Keq = 10.8.
A sample of this gas mixture was analyzed and found to contain 0.9 M NO, 1.7 M SO3, 0.07 M SO2, and 1.3 M NO2. Is the system at equilibrium? If so, explain why. If not, which way will it shift to reach equilibrium? (2 points)

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Answer #1

SO2(g) + NO2(g) NO(g) + SO3(g)

Reaction quotient,

Q = [NO][SO3]/[SO2][NO2]

    = (0.9)(1.7)/(0.07)(1.3)

    = 16.8

Given, the equilibrium constant, Keq = 10.8

Thus, Q Keq. Hence, the system is not at equilibrium.

Actually, Q > Keq. This implies that the system has more products than reactants.

Hence, the system will shift in the backward or reverse direction to reach equilibrium.

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