What is the osmolarity of a solution with 136 mmol/L of sodium ions in units of mOsmo/L, assuming that chloride is available in the same solution at the same concentration?
An osmole is 1 mol of particles that contribute to 1 osmotic pressure.
As in given case NaCl solution as provided that same concentration of Cl- as Na+ have in solution.
For example:
NaCl dissociates as one mole of Na+ and one mole of Cl-.Hence total 2 moles are used in osmotic pressure.
NaCl --------->Na+(aq) + Cl-(aq) (1mol of each is used for osmotic pressure i.e. known as OSmol).
Here number of osmoles = 2.
In given case Na+ concenteration is 136mmol/L and also given that same for Cl-.
hence ,Osmolarity =136mmol/L * 2 Osmole=272mOsmo/L.
Conclusion : In general,whenever a NaX(X is any halogen) solution dissociates it will form two osmoles.
and general formula for OSmolarity = concenteration of one of ion into * 2Osmol
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