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What is the ratio of acetate ion to acetic acid (Ka=1.76x10^-5) in a bugger containing these...

What is the ratio of acetate ion to acetic acid (Ka=1.76x10^-5) in a bugger containing these compounds at pH 3.290?

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Answer #1

Pka = -logka

       = -log1.76*10^-5

      = 4.75

PH   = PKa + log[acetate]/[acetic acid]

3.29   = 4.75 + log[acetate]/[acetic acid]

log[acetate]/[acetic acid] = 3.29-4.75

log[acetate]/[acetic acid]    = -1.46

[acetate]/[acetic acid]         = 10^-1.46

[acetate]/[acetic acid]         = 0.03467

[acetate]:[acetic acid]           = 0.03467 :1

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