Question

Bismuth oxide reacts with carbon to form bismuth metal: Bi2O3(s) + 3C(s) → 2Bi(s) + 3CO(g) When 661 g of Bi2O3 reacts with excess carbon, (a) how many moles of Bi form? mol Bi (b) how many grams of CO form?

Answer 1

Number of moles of Bi2O3 = 661g / 465.96 g/mol = 1.42 mole

from the balanced equation we can say that

1 mole of Bi2O3 produces 2 mole of Bi so

1.42 mole of Bi2O3 will produce

= 1.42 mole of Bi2O3*(2 mole of Bi / 1 mole of Bi2O3 )

= 2.84 mole of Bi

Therefore, the number of moles of Bi produced will be 2.84 mole

b) 1 mole of Bi2O3 produces 3 mole of CO so

1.42 mole of Bi2o3 will produce

= 1.42 mole of Bi2o3 *(3 mole of CO / 1 mole of Bi2O3)

= 4.26 mole of CO

1 mole of CO = 28.01 g

4.26 mole of CO = 119.3g

Therefore, the mass of CO produced would be 119.3 g