Question

calculate the {H3O+} and {OH-} for a solution with the following pH values: {H3O},{OH-} =  (separate...

calculate the {H3O+} and {OH-} for a solution with the following pH values:

{H3O},{OH-} = 
(separate by a comma on each)

1. pH= 10.3 (one significant figured)

2. pH=6.0 (one Sig fig)

3. pH= 7.35 (two sig fig)

4. pH=6.1 (one Sig fig)

5. pH= 1.24 (two sig fig) 

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Homework Answers

Answer #1

in general:

[H+] = 10^-pH

[OH-] = 10^-(14-pH)

so

q1

[H+] = 10^-pH = 10^-(10.3) = 5.01*10^-11

[OH-] = 10^-(14-pH) = 10^-(14-10.3) = 1.9952*10^-4

q2

[H+] = 10^-pH = 10^-(6)

[OH-] = 10^-(14-pH) = 10^-(14-6) = 10^-8

q3

[H+] = 10^-pH = 10^-(7.35) = 4.5*10^-8

[OH-] = 10^-(14-pH) = 10^-(14-7.35) = 2.2*10^-7

q4.

[H+] = 10^-pH = 10^-(6.1) = 8*10^-7

[OH-] = 10^-(14-pH) = 10^-(14-6.1) = 1*10^-8

q5

[H+] = 10^-pH = 10^-(1.24) = 0.05754 = 5.7*10^-2

[OH-] = 10^-(14-pH) = 10^-(14-1.24) = 1.737*10^-13 = 1.7*10^-13

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