Part A:
The decomposition of NI3 to form N2 and I2 releases −290.0 kJ of energy. The reaction can be represented as
2NI3(s)→N2(g)+3I2(g), ΔHrxn=−290.0 kJ
Find the change in enthaply when 15.0 g of NI3 decomposes.
Express your answer to three significant figures and include the appropriate units.
Part B:
4NH3(g)+5O2(g)→4NO(g)+6H2O(g)
Calculate the standard heat of reaction, or ΔH∘rxn, for this reaction using the given data. Also consider that the standard enthalpy of the formation of elements in their pure form is considered to be zero.
Reactant or product | ΔH∘f (kJ/mol) |
NH3(g) | -45.9 |
NO(g) | 91.3 |
H2O(g) | -241.8 |
Express your answer to four significant figures and include the appropriate units.
2NI3(s)→N2(g)+3I2(g), ΔHrxn=−290.0 kJ
2 moles of NI3 to gives -290Kj
2*394.72g of NI3 to gives -290KJ
15g of NI3 to gives = -290*15/2*394.72 =-5.51KJ
part-B
4NH3(g)+5O2(g)→4NO(g)+6H2O(g)
ΔH∘rex = ΔH∘f products - ΔH∘f reactant
= 6*-241.8+4*91.3-(4*-45.9+5*0)
= -902.0KJ
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