Question

A 0.505 g sample of KCl is added to 61.0 g of water in a calorimeter....

A 0.505 g sample of KCl is added to 61.0 g of water in a calorimeter. If the temperature decreases by 1.06°C, what is the approximate amount of heat (in J) involved in the dissolution of the KCl, assuming the heat capacity of the resulting solution is 4.18 J/g°C?

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Answer #1

Heat of the reaction is equal to heat given off on dissolution of salt in water

Qreaction=−Qsolution

The minus sign indicate heat is lost

We know

Qsolution=m*c*

mass of water m =61gm

Specific heat capacity C= 4.184 J/(g*°C)

Change in temperature ​​​​​​ is -1.06°C (minus because temperature decreases

Qsolution= -61g*1.06°c*4.184 J/(g*°c)=-270.53J

Qreaction =-Qsolution=-(-270.53J)=270.53 J

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