Question

how many moles of NaOH are present in 12.5mL of .210 M NaOH?

Answer 1

Answer –

We are given, molarity of NaOH = 0.210 M , volume of NaOH = 12.5 mL

For the purpose of the mole of NaoH first we need to convert given volume mL to L

We know,

1 mL = 0.001 L

So, 12.5 mL = ?

= 0.0125 L

Now we need to use formula for molarity to calculate moles,

Molarity = moles / volume (L)

So, moles = molarity * volume (L)

                 = 0.210 M * 0.0125 L

                 = 0.00263 moles of NaOH

So, 0.00263 moles of NaOH are present in 12.5mL of .210 M NaOH