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8. Use the following half-reactions to write a balanced full reaction for the reduction of iron...

8. Use the following half-reactions to write a balanced full reaction for the reduction of iron (II) by copper, and compute the standard electromotive force for this reaction (spectator ions are not required).

Also calculate the Gibbs energy for this reaction!

Cu+ + e − → Cu E◦ = +0.52 V (1)

F e2+ + 2e − → F e E◦ = −0.44 V (2)

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Answer #1

Fe(s) ------------> Fe^2+ (aq) + 2e^-       E0 = 0.44v

2Cu^+ (aq) + 2e^- ------> 2Cu(s)           E0 = 0.52v

--------------------------------------------------------------------

Fe(s) + 2Cu^+ (aq) -----> Fe^2+ (aq) + 2Cu(s)     E0cell = 0.96v

n = 2

F = 96500c

G0     = -nE0cell*F

               = -2*0.96*96500

               = -185280J/mole

               = -185.28KJ/mole  

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