Question

What is the final temperature (in oC) of a 38 g sample of aluminum (specific heat = 0.900 J/(g K)) which absorbs 89.9 kJ of heat when it warms from 74.6oC?

Answer 1

Heat gain by a sample is
mCp = heat gain or loss { in our case it is gaining heat as temperature is increasing}

where m = mass of sample in g
   Cp = specific heat of sample in J/gK
   = change in temperature = (T_final - T_initial)

Given m = 38g
Cp = .900J/gK
= ?

converting KJ to Joule
1KJ = 1000J

89.9KJ = 89900J

from heat balance equation

89900J = 38g*0.9J/gK *

= 89900J/(38g*0.9J/gK) = 2628.65K
T_initial=74.6^oC+273 =347.6K
= (T_final - T_initial) = 2628.6K
T_final = 2628.6K+347.6K = 2976.2K = 2703.2^oC