Fill in the empty squares
[H+] |
pH |
[OH-] |
pOH |
Acid, Base , Neutral |
0.01 M |
||||
1 x 10-8M |
||||
10 |
1)
we know that
pH = -log [H+] = -log 0.01 = 2
now
[H+] [OH-] = 10-14
0.01 [OH-] = 10-14
[OH-] = 10-12
now
pOH = -log [OH-] = -log 10-12 = 12
now
pH < 7 , it is acidic
2)
pOH = -log [OH-] = -log 10-8 = 8
[H+] [OH-] = 10-14
[H+] x 10-8 = 10-14
[H+] = 10-6
pH = -log [H+] = -log 10-6 = 6
as pH < 7 , it is acidic
3)
pH = -log [H+]
10 = -log [H+]
[H+] = 10-10
now
[H+] [OH-] = 10-14
10-10 [OH-] = 10-14
[OH-] = 10-4
pOH = -log [OH-]
pOH = -log 10-4 = 4
as
pH > 7 , it is basic
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