For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.
(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)
1. | _____ silver chromate | A. Ag3PO4 | ||
2. | _____ iron(III) hydroxide | B. Zn3(PO4)2 | ||
C. Ni(OH)2 | ||||
D. BaF2 |
******The first part above can have more than one answer (example A,B) ****
Please only answer this if you are 100% confident as I am down to my last attempt... Thanks!
Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.
silver chromate |
iron(III) hydroxide |
|||
Ksp = ____ |
Ksp = ____ |
Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.
Recal that
Ksp = [A]^a[B]^b
for
Silver chromate --> Ag2CrO4 --> 2Ag+ + CrO4-2 --> type 2A + B
Ag3PO4 = 3A + B
Zn3(PO4)2 --> 3A + 2B
Ni(OH)2 --> A + 2B
BaF2 --> A + 2B
note that 2A + B <-> A + 2B
so
silver chromate can be compared directy with Ni(OH)2 and BaF2
Q2.
for Iron III hydroxide --> Fe(OH)3 --> Fe+3 + 3OH- --> A + 3B type
so
Ag3PO4 = 3A + B
Zn3(PO4)2 --> 3A + 2B
3A + B <-> A + 3B
only Ag3P4 can be compared
Q3.
K in terms f "S" for each salt:
Ag2CrO4 --> 2Ag+ + CrO4-2
Ksp = [Ag+]^2[CrO4-2]
Let S be 1 mol of salt so
[Ag+] = 2S and CrO4-2 = S
Ksp = (2S)^2(S)
Ksp = 4S^3
Fe(OH)3 --> Fe+3 + 3OH-
Ksp = [Fe+3][OH-]^3
1 mol of salt = S
Fe+3 = S
OH- = 3S
Ksp = (S)(3S)^3
Ksp = 27S^4
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