Question

carbon tetrachloride has a specific gravity of 1.590 what is the volume in ml of a sample of carbon tetrachloride that has a mass of 1.8 kg

Answer #1

specific gravity as the ratio of the specific weight of fluid to the specific weight of a standard fluid (water).

Specific gravity of CCl_{4} = specific weight of
CCl_{4} / specific weight of water = 1.59

or, specific weight of CCl_{4} /(9.81 X 10^{2}
N/m^{3}) = 1.59

or, specific weight of CCl_{4} = 15590
N/m^{3}

The weight of carbon tetrachloride = W = mg = 1.8 kg X 9.81
m/s^{2} = 17.658 N

The specific weight of carbon tetrachloride is its weight per unit volume = 17.658 N/Volume

or 15590 N/m^{3} = 17.658 N/Volume

or, Volume = 17.658 N/15590 N/m^{3} = **1.13 X
10 ^{-3} m^{3} = 1.13 L**

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