Question

carbon tetrachloride has a specific gravity of 1.590 what is the volume in ml of a sample of carbon tetrachloride that has a mass of 1.8 kg

Answer 1

specific gravity as the ratio of the specific weight of fluid to the specific weight of a standard fluid (water).

Specific gravity of CCl₄ = specific weight of CCl₄ / specific weight of water = 1.59

or, specific weight of CCl₄ /(9.81 X 10² N/m³) = 1.59

or, specific weight of CCl₄ = 15590 N/m³

The weight of carbon tetrachloride = W = mg = 1.8 kg X 9.81 m/s² = 17.658 N

The specific weight of carbon tetrachloride is its weight per unit volume = 17.658 N/Volume

or   15590 N/m³ = 17.658 N/Volume

or, Volume = 17.658 N/15590 N/m³ = 1.13 X 10^-3 m³ = 1.13 L