carbon tetrachloride has a specific gravity of 1.590 what is the volume in ml of a sample of carbon tetrachloride that has a mass of 1.8 kg
specific gravity as the ratio of the specific weight of fluid to the specific weight of a standard fluid (water).
Specific gravity of CCl4 = specific weight of CCl4 / specific weight of water = 1.59
or, specific weight of CCl4 /(9.81 X 102 N/m3) = 1.59
or, specific weight of CCl4 = 15590 N/m3
The weight of carbon tetrachloride = W = mg = 1.8 kg X 9.81 m/s2 = 17.658 N
The specific weight of carbon tetrachloride is its weight per unit volume = 17.658 N/Volume
or 15590 N/m3 = 17.658 N/Volume
or, Volume = 17.658 N/15590 N/m3 = 1.13 X 10-3 m3 = 1.13 L
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