if 10.57 mL of an acetic Acid solution required 10.54 mL 0.9607 M NaOH to reach the endpoint, whats the concentration?
Write the reaction between NaOH and acetic acid
CH3COOH + NaOH --- > CH3COONa + H2O
Mol ratio between NaOH and CH3COOH is 1 : 1
Step 1 calculate moles of NaOH
n NaOH = volume in L x molarity
Step 2 Calculate the moles of CH3COOH
n CH3COOH = moles of NaOH x 1 mol CH3COOH/ 1 mol NaOH
0.01013*1/1=0.01013 mol CH3COOH
Step 3 use volume of acid to calculate concentration
[CH3COOH]= 0.01013 mol / 0.01057 L
Concentration of acetic acid is 0.96 M
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