Question

A flask is charged with 1.500 atm N2O4(g) and 1.00 atm NO2(g) at 25 °C and...

A flask is charged with 1.500 atm N2O4(g) and 1.00 atm NO2(g) at 25 °C and the following equilibrium is achieved: N2O4(g)<-------> 2NO2(g)

After equilibrium is reached, the partial pressure of NO2 is 0.512 atm. What is the equilibrium partial pressure of N2O4?

Homework Answers

Answer #1

Temperature does not have influence on moles

Consider partial pressures as moles. No. moles is proportional to pressure or volume.

NO2 used = 1 - 0.512 = 0.488 atm

extra N2O4 = 1/2 x 0.488atm = 0.244atm
partial prressure of N2O4 = 1.5 + 0.244 = 1.744atm

ICE table can be written as follows to better understand

Answer: The equilibrium partial pressure of N2O4 = 1.744atm

Thank You!

Please rate this answer by clicking on "Thumbs Up" icon to support me, if this answer finds correct and helpful.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A flask is charged with 1.500 atm of N2O4(g) and 1.00 atm NO2(g) at 25 ∘C,...
A flask is charged with 1.500 atm of N2O4(g) and 1.00 atm NO2(g) at 25 ∘C, and the following equilibrium is achieved: N2O4(g)⇌2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.514 atm . Calculate Kc for the reaction.
A flask is charged with 1.800 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and...
A flask is charged with 1.800 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and the following equilibrium is achieved: N2O4(g)⇌2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.515 atm . What is the equilibrium partial pressure of N2O4? Calculate the value of Kp for the reaction Calculate Kc for the reaction.
A flask is charged with 1.800atm of N2O4(g) and 1.00 atm NO2(g) at 25 ?C, and...
A flask is charged with 1.800atm of N2O4(g) and 1.00 atm NO2(g) at 25 ?C, and the following equilibrium is achieved: N2O4(g)?2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.512atm . Calculate Kc for the reaction.
A flask is charged with 1.800 atm of N2O4(g) and 1.00 atm of NO2(g) at 25...
A flask is charged with 1.800 atm of N2O4(g) and 1.00 atm of NO2(g) at 25 ∘C , and the following equilibrium is achieved: N2O4(g)⇌2NO2(g) After equilibrium is reached, the partial pressure of NO2 is 0.519 atm . Part A: What is the partial pressure of N2O4 at equilibrium? Part B: Calculate the value of Kp for the reaction.​ Part C: Calculate the value of Kc for the reaction.​
A flask is charged with 1.800 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and...
A flask is charged with 1.800 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and the following equilibrium is achieved: N2O4(g)⇌2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.517 atm . 1)What is the equilibrium partial pressure of N2O4? Express your answer with the appropriate units. 2)Calculate the value of Kp for the reaction. 3)Calculate Kc for the reaction.
A flask is charged with 1.550 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and...
A flask is charged with 1.550 atm of N2O4(g)and 1.00 atm NO2(g) at 25 ∘C, and the following equilibrium is achieved: N2O4(g)⇌2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.519 atm . 1.What is the equilibrium partial pressure of N2O4?Express your answer with the appropriate units. 2. Calculate the value of Kp for the reaction. 3.Calculate the value of Kc for the reaction.
At a particular temperature, Kp=0.22 for the reaction N2O4(g)=2NO2(g) A flask containing only NO2 at an...
At a particular temperature, Kp=0.22 for the reaction N2O4(g)=2NO2(g) A flask containing only NO2 at an initial pressure of 5.8 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases.
An equilibrium mixture consists of 0.31 atm NO2(g) and 0.45 atm N2O4(g). 2 NO2(g) <—> N2O4(g)...
An equilibrium mixture consists of 0.31 atm NO2(g) and 0.45 atm N2O4(g). 2 NO2(g) <—> N2O4(g) A chemist adds enough NO2 to this mixture to increase the equilibrium partial pressure of NO2(g) to 0.40 atm. What additional pressure of NO2 did she add to the container? Assume that the temperature and volume remain constant.
At 25°C, the equilibrium partial pressures of NO2 and N2O4 are 0.150 atm and 0.200 atm,...
At 25°C, the equilibrium partial pressures of NO2 and N2O4 are 0.150 atm and 0.200 atm, respectively. If the volume is increased by 1.60 fold at constant temperature, calculate the partial pressures of the gases when a new equilibrium is established. PNO2 = atm PN2O4 = atm
Calculate the equilibrium concentrations of N2O4 and NO2 at 25 ∘C in a vessel that contains...
Calculate the equilibrium concentrations of N2O4 and NO2 at 25 ∘C in a vessel that contains an initial N2O4 concentration of 0.0507 M . The equilibrium constantKc for the reaction N2O4(g)⇌2NO2(g) is 4.64×10−3 at 25 ∘C.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT