A flask is charged with 1.500 atm N2O4(g) and 1.00 atm NO2(g) at 25 °C and the following equilibrium is achieved: N2O4(g)<-------> 2NO2(g)
After equilibrium is reached, the partial pressure of NO2 is 0.512 atm. What is the equilibrium partial pressure of N2O4?
Temperature does not have influence on moles
Consider partial pressures as moles. No. moles is proportional
to pressure or volume.
NO2 used = 1 - 0.512 = 0.488 atm
extra N2O4 = 1/2 x 0.488atm = 0.244atm
partial prressure of N2O4 = 1.5 + 0.244 = 1.744atm
ICE table can be written as follows to better understand
Answer: The equilibrium partial pressure of N2O4 = 1.744atm
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