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At 25 °C, CaCrO4 (s) < ------- > Ca2+ (aq) + CrO42- (aq) has an equilibrium...

At 25 °C, CaCrO4 (s) < ------- > Ca2+ (aq) + CrO42- (aq) has an equilibrium constant Kc = 7.1 x 10-4. What are the equilibrium concentrations of Ca2+ and CrO42- in a saturated solution of CaCrO4?

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Answer #1

equilibrium constant Kc = 7.1 x 10^-4.

CaCrO4 (s) < ------- > Ca2+ (aq) + CrO42- (aq)

                                     S                  S

Kc = [Ca+2][CrO42-]

7.1 x 10^-4 = S^2

S = 0.0266 M

equilibrium concentrations of Ca2+ and CrO42- = 0.0266 M

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