Question

Aqueous hydrobromic acid

HBr

will react with solid sodium hydroxide

NaOH

to produce aqueous sodium bromide

NaBr

and liquid water

H2O

. Suppose 15. g of hydrobromic acid is mixed with 11.4 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

Balanced equation is

HBr + NaOH ------> NaBr + H2O

Number of moles of HBr = 15g / 80.91 g/mol = 0.185 mole

Number of moles of NaOH = 11.4 g / 40.0 g/mol = 0.285 mole

from the balanced equation we can say that

1 mole of HBr requires 1 mole of NaOH so

0.185 mole of HBr will require 0.185 mole of NaOH

but we have 0.285 mole of NaOH which is in excess so

HBr is limiting reactant

1 mole of HBr produces 1 mole of NaBr so

0.185 mole of Hbr will produces 0.185 mole of NaBr

1mole of NaBr = 102.894 g

so 0.185 mole of NaBr = 19.0g

Therefore, the mass of NaBr produced will be 19.0 g