Question

a total of 2 kilograms of a dilute aqueous 5% with phosphoric acid solution are required....

a total of 2 kilograms of a dilute aqueous 5% with phosphoric acid solution are required. technical grade concentrated phosphoric acid is available that contains 85.2% pure acid. how many grams (a) of technical grade acid and how many grams (b) of water are required?

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Answer #1

Total mass of solution required = 2 kg = 2000 g

Mass of phosphoric acid in teh solution = 0.05 x 2000 = 100 g

Now it is given that technical grade concentrated phosphoric acid is available that contains 85.2% pure acid

=> 100 g of technical grade contains 85.2 g phosphoric acid

For 85.2 g phosphoric acid, mass of technical grade concentrated phosphoric acid needed = 100

=> For 100 g phosphoric acid, mass of technical grade concentrated phosphoric acid needed = (100 / 85.2) x 100 = 117.37 g

=> Mass of technical grade acid = 117.37 g

Mass of Water = 2000 - 117.37 = 1882.63 g

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