Question

A foundry worker places a 5.75 kg sheet of nickel at a temperature of 19°C on top of a 16.6 kg sheet of palladium at 66°C. Assuming no heat is lost to the surroundings, calculate the final temperature of the two sheets of metal.

Answer 1

specific heat capacity of Ni = 0.440 J/g.oC

specific heat capacity of Pd = 0.240 J/g.oC

Let us denote Ni by symbol 1 and Pd by symbol 2

m1 = 5750.0 g

T1 = 19.0 oC

C1 = 0.44 J/goC

m2 = 16600.0 g

T2 = 66.0 oC

C2 = 0.24 J/goC

T = to be calculated

Let the final temperature be T oC

use:

heat lost by 2 = heat gained by 1

m2*C2*(T2-T) = m1*C1*(T-T1)

16600.0*0.24*(66.0-T) = 5750.0*0.44*(T-19.0)

3984*(66.0-T) = 2530*(T-19.0)

262944 - 3984*T = 2530*T - 48070

T= 47.7 oC

Answer: 47.7 oC