Calculate the percent dissociation of HNO2 (Ka=4.5×10−4) in 0.050 M HNO2.
Ka = 4.5 x 10^-4
concentration of HNO2 = 0.050 M
HNO2 -----------> NO2- + H+
0.05 0 0
0.05 - x x x
Ka = x^2 / 0.05 - x
4.5 x 10^-4 = x^2 / 0.05 - x
x = 4.52 x 10^-3
% dissociation = x / [H+] ) x 100
= (4.52 x 10^-3 /0.05) x 100
% dissociation = 9.04 %
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