Complete the following table by calculating the missing
entries. In each case indicate whether the solution is acidic or
basic.
pH | pOH | [H+] | [OH -] | acidic or basic? |
9.09 | M | M |
acidic basic |
|
3.92 | M | M |
acidic basic |
|
8.80 x 10-11 M | M |
acidic basic |
||
M | 8.50 x 10-2 M |
acidic basic |
1.
pH = 9.09
pOH = 14 - pH = 14 - 9.09 = 4.91
[H+] = 10^(-pH) = 10^(-9.09) = 8.13*10^-10 M
[OH-] = 10^(-pOH) = 10^(-4.91) = 1.23*10^-5 M
Basic since [OH-]>[H+]
2.
pOH = 3.92
pH = 14 -pOH = 14 - 3.92 =10.08
[H+] = 10^(-10.08) = 8.32*10^-11 M
[OH-] = 10^(-3.92) = 1.2*10^-4 M
Basic since [OH-]>[H+]
3.
[H+] = 8.8*10^-11 M
[OH-] = 10^-14/ [H+] = 10^-14 /(8.8*10^-11) = 1.14*10^-4
M
pH = - log [H+] = -log (8.8*10^-11 )= 10.06
pOH = 14 - pH = 14 - 10.06 = 3.94
Basic since [OH-]>[H+]
4.
[OH-] = 8.5*10^-2 M
[H+] = 10^-14/ [OH-] = 10^-14 /(8.5*10^-2) = 1.18*10^-13
M
pH = - log [H+] = -log (1.18*10^-13 )= 12.93
pOH = 14 - pH = 14 - 12.93 = 1.07
Basic since [OH-]>[H+]
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