Question

# Complete the following table by calculating the missing entries. In each case indicate whether the solution...

Complete the following table by calculating the missing entries. In each case indicate whether the solution is acidic or basic.

 pH pOH [H+] [OH -] acidic or basic? 9.09 M M acidic basic 3.92 M M acidic basic 8.80 x 10-11 M M acidic basic M 8.50 x 10-2 M acidic basic

1.
pH = 9.09
pOH = 14 - pH = 14 - 9.09 = 4.91
[H+] = 10^(-pH) = 10^(-9.09) = 8.13*10^-10 M
[OH-] = 10^(-pOH) = 10^(-4.91) = 1.23*10^-5 M

Basic since [OH-]>[H+]

2.
pOH = 3.92
pH = 14 -pOH = 14 - 3.92 =10.08
[H+] = 10^(-10.08) = 8.32*10^-11 M
[OH-] = 10^(-3.92) = 1.2*10^-4 M
Basic since [OH-]>[H+]

3.
[H+] = 8.8*10^-11 M
[OH-] = 10^-14/ [H+] = 10^-14 /(8.8*10^-11) = 1.14*10^-4 M

pH = - log [H+] = -log (8.8*10^-11 )= 10.06
pOH = 14 - pH = 14 - 10.06 = 3.94
Basic since [OH-]>[H+]

4.
[OH-] = 8.5*10^-2 M
[H+] = 10^-14/ [OH-] = 10^-14 /(8.5*10^-2) = 1.18*10^-13 M

pH = - log [H+] = -log (1.18*10^-13 )= 12.93
pOH = 14 - pH = 14 - 12.93 = 1.07
Basic since [OH-]>[H+]

#### Earn Coins

Coins can be redeemed for fabulous gifts.