the potentials available
SiO2(s) + 4 H+ + 4 e− ⇌ Si(s) + 2 H2O −0.91
O2(g) + 2 H2O + 4 e− ⇌ 4 OH−(aq) +0.401
add both equations:
invert (1)
Si(s) + 2 H2O ⇌SiO2(s) + 4 H+ + 4 e− E = 0.91 this is going to OXIDIZE
O2(g) + 2 H2O + 4 e− ⇌ 4 OH−(aq) +0.401 This is going to REDUCE
Add all
O2(g) + 2 H2O + 4 e− + Si(s) + 2 H2O ⇌SiO2(s) + 4 H+ + 4 e− + 4 OH−(aq) Etotal = 0.91 + 0.401 = 1.311
cancel common terms
O2(g) + 4H2O + Si(s) ⇌SiO2(s) + 4H2O(l) Etotal = 0.91 + 0.401 = 1.311
cancel water
O2(g) + Si(s) ⇌SiO2(s) Etotal = 1.311
for dG:
dG = -nF*E°cell
we know E|cell = 1.311
dG = -nF*E°cell
n = 4 elecxtrons transfer , F = 96500,
dG = -4*96500 * 1.311 = -506046 J/mol
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