Question

When N2* relaxes back to the ground state it emits a photon of
wavelength 470 nm, which makes up part of the aurora’s lights.
Calculate the energy difference between the MOs involved in the
transition.

Answer #1

We know that Energy difference, E = hc / λ

Where

h = plank's constant = 6.625x 10^{-34} Js

c = speed of light = 3x 10^{8} m/s

λ = wave length of emitted light = 470 nm = 470x10^{-9}
m

Plug the values we get E = (6.625x 10^{-34} Jsx3x
10^{8} m/s)/(470x10^{-9} )

= 4.23x10^{-19} J

Therefore the energy difference between the MOs involved in the
transition is 4.23x10^{-19} J

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