Consider the reaction
5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l)
The average rate of consumption of Br− is 1.16×10−4M/s over the first two minutes. What is the average rate of formation of Br2 during the same time interval?
Express your answer with the appropriate units.
5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l)
rate of reaction in terms of Br- is
rate of reaction = (1/5)*average rate of consumption of Br-
rate of reaction in terms of Br2 is
rate of reaction = (1/3)*average rate of formation of Br2
equating both
(1/3)*average rate of formation of Br2 = (1/5)*average rate of consumption of Br-
average rate of formation of Br2 = (3/5)*average rate of consumption of Br-
= (3/5)*(1.16*10^-4 M/s)
= 6.96*10^-5 M/s
Answer: 6.96*10^-5 M/s
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