Kb for ammonia (NH3 ) at 310 K is
1.85*10-5 , and Kw for water at 310 K is
2.42*10-14 . What is the pH of a 10 uM solution of
ammonia at 310 K?
Kb = 1.85 x 10^-5
concentration of NH3 = 10 x 10^-6 M
NH3 + H2O ---------------> NH4+ + OH-
10^-5 0 0
10^-5 - x x x
Kb = x^2 / 10^-5 - x
1.85 x 10^-5 = x^2 / 10^-5 - x
x = 7.20 x 10^-6
[OH-] = 7.20 x 10^-6 M
pOH = -log (7.20 x 10^-6 )
pOH = 5.14
pH = 8.86
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