Find Veq for the titration of 25.00 mL of 0.3344 M glycolic acid with 0.1055 M NaOH. Answer in units of mL to 2 decimal places
Q:- Find Veq for the titration of 25.00 mL of 0.3344 M glycolic acid with 0.1055 M NaOH. Answer in units of mL to 2 decimal places
Ans :-
Balanced chemical reaction during titration is .
HOCH2COOH + NaOH --> HOCH2COO- Na+ + H2O
Volume of acid V1 = 25 ml
Concentration of acid (Molarity ) M1 = 0.3344 M
Concentration of base M2 = 0.1055 M
Volume of base V2 = ?
molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base
lets put the values in formula
25 * 0.3344 = 0.1055 * V2
79.24 ml = V2
V2 = 79.24 ( with 2 decimal places )
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