aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water. suppose 36. g of hydrochloric acid is mixed with 21.0 g of sodium hydroxide . Calculate the minimum of hydrochloric acid that could be left over by the chemical reaction round your answer to 2 sig figs
HCl + NaOH --------------> NaCl + H2O
no of moles of HCl = W/G.M.Wt
= 36/36.5 = 0.986 moles
no of moles of NaOH = W/G.M.Wt
= 21/40 = 0.525 moles
from balanced equation
1 mole of HCL react with 1 mole of NaOH
HCl is excess reagent
left no of moles of HCl = 0.986-0.525 = 0.461 moles
mass of HCl is left = 0.461 *36.5 = 17g of HCl
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