Question

Calculate the mass of KHC8H4O4 (molar mass = 204.23 g/mol) that reacts with 25.0 mL of 0.150 M NaOH solution. KHC8H4O4(aq) + NaOH(aq) → H2O(l) + NaKC8H4O4(aq) a)0.383 g b)0.766 g c)1.88 g d)1.53 g e)3.75 g

Answer 1

Number of moles of NaOH = molarity * volume of solution in L

Number of moles of NaOH = 0.150 * 0.025 L = 0.00375 mole

From the balanced equation we can say that

1 mole of NaOH requires 1 mole of KHC8H4O4 so

0.00375 mole of NaOH will require

= 0.00375 mole of NaOH *(1 mole of KHC8H4O4 / 1 mole of NaOH)

= 0.00375 mole of KHC8H4O4

mass of 1 mole of KHC8H4O4 = 204.23 g so

the mass of 0.00375 mole of KHC8H4O4 = 0.766 g

Therefore, the mass of KHC8H4O4 = 0.766 g

option B is correct