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In an enzymatic fermentation, the initial concentration of sugar is 0.16 mol/L; after 10.0 hours the...

In an enzymatic fermentation, the initial concentration of sugar is 0.16 mol/L; after 10.0 hours the concentration is 0.080 mol/L; after 20.0 hours the concentration is 0.040 mol/L. What is the order of this reaction, and what is the rate constant?

answer : first order; 1.93 x 10-5 s-1

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Answer #1

initial concentration(a0) = 0.16 M

after 10 hr , concentration = 0.08 M

after 20 hr, concentration = 0.04 M

from the above data, after every 10 hr , the concentraion become half .so that

half life time = 10 hr, and this type of trend is observed for first order reactions.

so that,

rate constant(k) = 0.693/T1/2

                 = 0.693/(10*60*60)

                 = 1.925*10^-5 s-1

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